Hess's law allows the enthalpy change (ΔH) for a reaction to be calculated even when it cannot be measured directly. This is accomplished by performing basic algebraic operations based on thechemical equation of reactions using previously determined values for the enthalpies of formation.
How To Calculate Using Hess Law??Let us finding out!!!
1) Calculate the heat released by the burning of sulfur in oxygen given the following steps
Given Steps
2S(s) + 3O2 (g) 2SO3(g) H = ?
Answer:
Step 1 S(s) + O2 (g) SO2 (g) H= -297 kJStep 2 2SO2 (g) + O2 (g) 2SO3 (g) H= - 198 kJ
1) The overall reaction is written above.
Note that sulfur (S) is a reactant and sulfur trioxide (SO3) is the product. Therefore neither reaction in steps 1 or 2 needs to be reversed.2) Manipulate equations
Note that the overall equation has 2 moles of S and 2 moles of SO3. Therefore the first reaction must be multiplied by two , but the second can be left alone.
3) Add equations and heatsSubstances in bold above will be products
Step 1 2 S(s) + 2O2 (g) 2SO2 (g) H = - 594 kJStep 2 2 SO2(g) + O2 (g) 2 SO3 (g) H = - 198 kJ
Addition: 2S (s) + 3O2 (g) + 2SO2 (g) 2SO2 (g) + 2SO3 (g) H = - 792 kJSubstances in bold above are common and are therefore canceled
Net 2S (s) + 3O2 (g) 2 SO3 (g) H = - 792 kJ
The oxidation of nitrogen to produce nitrogen dioxide. The enthalpy change ΔH of the reaction is 68 kJ
N2(g) + 2O2(g) = 2NO2(g) ΔH = 68 kJ
This reaction also can be carried out in two distinct steps:
N2(g) + O2(g) = 2NO(g) ΔH1 = 180 kJ
2NO(g) + O2(g) = 2NO2(g) ΔH2 = -112 kJ
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Net reaction: N2(g) + 2O2(g) = 2NO2(g)
ΔH = ΔH1 + ΔH2 = 68 kJ
From that example,we can know how to calculate enthalpy change..we should try it!!
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